3) Determine [Ba 2+] and [PO 4 3 ¯]: Example 1. ? The formula for K sp is: K sp = [Ag + ] [I –] K sp = s 2 = 8.5 x 10 -17. where s is the concentration of each ion at equilibrium. Calculate the molar solubility of Fe(OH)2 when buffered at pH = 10.1. An example of an insoluble substance, AgBr (silver bromide), has a minuscule molar solubility with the value being close to 5.71 x 10 to the … moles of solute in 100 mL; S = 0.0016 g / 78.1 g/mol = \(2.05 \times 10^{-5}\) mol \[S = \dfrac{2.05 \times 10^{ –5} mol}{0.100\; L} = 2.05 \times 10^{-4} M\] even though it is immportant ffor calculating Ka and Kb. Example #1: Silver chloride, AgCl, has a K sp = 1.77 x 10¯ 10. The molar solubility of AgI is 9.0 x 10 -9 mol/L. What is the molar solubility of MgF 2 in a 0.20 M solution of NaF? It is a constant property of each substance - for example, the molar mass of water is approximately equal to 18 g/mol. Solution. But we have [OH-]= 1.26 x 10^-4 M so at equilibrium: Ksp = manufactured from the ions. Use the ksp value and [OH-] above to find [Fe+2]. President Trump lashes out at 'lightweight' reporter, Seymour, 69, clarifies remark on being able to play 25, People can’t believe Trump’s tiny desk isn’t a joke, NFL player's neck injury may end his career, Aniston introduces 'newest member of our family', The 20 jobs most at risk because of the pandemic, Sleuths find Utah monolith, but mystery remains, Here are Amazon's best Black Friday deals, Matthew Perry engaged to 'the greatest woman', Tired of mockery, Austrian village changes name, Donor sues over failure to expose election fraud. b.) I thought I knew how to work them but keep coming up with the wrong answer for both. Calculate the K sp for Ba 3 (PO 4) 2. Join Yahoo Answers and get 100 points today. I went to a Thanksgiving dinner with over 100 guests. Example #10: The molar solubility of Ba 3 (PO 4) 2 is 8.89 x 10¯ 9 M in pure water. K sp (MgF 2) = 8.0 x 10-8.. I thought I knew how to work them but keep coming up with the wrong answer for both. The solubility of barium sulphate at 298 K is 1.05 x 10-5 mol dm-3. a.) calculate the molar solubility of Ag2CrO4 AT 25 C in: a- pure water b- 0.200M AgNO3 C- 0.200M Na2CrO4 for Ag2CrO4 AT 25C, Ksp=1.2x10^(-12) Which of the following compounds is most soluble in water? Still have questions? Draw structures of OF2, BrF3, SCl2, XeF4, PF3 in a way that indicates their molecular shape? It is expressed in grams per mole. Should I call the police on then? pOH = - log[OH-] = 3.9 to find conc. Molar solubility (M) is a measure of the ability of a compound, called a solute, to dissolve in a specific substance, called a solvent.Specifically, it is the maximum number of moles of a solute that are able to dissolve in one liter of solvent, so molar solubility is measures as moles/L. The solubility of CaF 2 (molar mass 78.1) at 18°C is reported to be 1.6 mg per 100 mL of water. Solution: 1) Write the chemical equation for the dissolving of barium phosphate in water: Ba 3 (PO 4) 2 (s) ⇌ 3Ba 2+ (aq) + 2PO 4 3 ¯(aq) 2) Write the K sp expression for barium phosphate: K sp = [Ba 2+] 3 [PO 4 3 ¯] 2. If 50.0 mL of 0.540 mol/L sodium hydroxide reacts with 85.6 mL of sulfuric acid, calculate the concentration of the sulfuric acid. An example of a soluble substance is NaNO 3 (sodium nitrate), which has a high molar solubility with 10.0+ moles per liter of solution most of the time. I thought I knew how to work them but keep coming up with the wrong answer for both. Calculate the molar solubility of Fe(OH)2 when buffered at pH = 10.1. well assuming that the value of 0.01835 M ( 1.835 X 10^-2 M ) is the correct and represents the amount of Ca(OH)2 in a std solution ..then the formal solubility is 1.835 x 10^-2 M..the amount of Ca+2 is 1.835 X 10^-2 M, the amount of OH^-1 = 3.67 x 10^-2 M, the solubility … Molar mass is the mass of 1 mole of the solute.

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